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Tell me? - Ifofis, the molar solubility ofin 0.1 Mis : - Solutions - JEE Main

If K_{sp} of Ag_{2}CO_{3} is 8 \times 10^{-12}, the molar solubility of Ag_{2}CO_{3} in 0.1 M AgNO_{3} is :

  • Option 1)

    8 \times 10^{-11} M

     

  • Option 2)

    8 \times 10^{-12}

  • Option 3)

    8 \times 10^{-10}

  • Option 4)

    8 \times 10^{-13} M

Answers (1)
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Relation between concentration terms (Molality & Mole fraction) -

m= \frac{x_{solute}\times 1000}{x_{solvent}\times M_{1}}

- wherein

M_{1}= Molecular\ Mass\ of \ Solvent

x_{solute}= mole\: f\! raction\ of\ solute 

x_{solvent}= mole\: f\! raction\ of\ solvent

 

 

 

Relation between concentration terms (Molality & Molarity) -

\dpi{100} m=\frac{1000M}{1000d-Mm_{1}}

- wherein

m=Molality

M=Molarity

m_{1}=Molar\: mass\: of \: solute

\dpi{100} d=density\: of \: solution \: g/ml

As we have learned in solution

The reaction is

Ag_{2}CO_{3}(s)\rightleftharpoons 2Ag+(aq)(0.1+25)M+CO{_{3}}^{-2}(aq)(s\: M)

Ksp =\left [ Ag^{+} \right ]^{2}\left [ CO{_{3}}^{-2} \right ]

8\times 10^{-12}=(0.1+25)^{2}(s)

s=8\times 10^{-10}M

 

 

 


Option 1)

8 \times 10^{-11} M

 

Option 2)

8 \times 10^{-12}

Option 3)

8 \times 10^{-10}

Option 4)

8 \times 10^{-13} M

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