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In Bohr series of lines of hydrogen spectrum, the third line from the red end corresponds to which one of the following inter­orbit jumps of the electron for Bohr orbits in an atom of hydrogen?

  • Option 1)

    3\rightarrow 2

  • Option 2)

    5\rightarrow 2

  • Option 3)

    4\rightarrow 1

  • Option 4)

    2\rightarrow 5

 

Answers (2)

best_answer

As we learnt in 

Line Spectrum of Hydrogen like atoms -

\frac{1}{\lambda }= RZ^{2}\left ( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right )

 

- wherein

Where R is called Rhydberg constant, R = 1.097 X 107 , Z is atomic number

n1= 1,2 ,3….

n2= n1+1, n1+2 ……

 

 

The electron has minimum energy in the first orbit and its energy increases as n increases. Here nrepresents number of orbit, The third line from the red end corresponds to yellow region i.e.5. In order to obtain less energy electron tends to come in 1st or 2nd orbit. So jump may be involved either 5\rightarrow 1\: or\: 5\rightarrow 2. Thus 5\rightarrow 2 is correct


Option 1)

3\rightarrow 2

Incorrect option

Option 2)

5\rightarrow 2

Correct Option

Option 3)

4\rightarrow 1

Incorrect option

Option 4)

2\rightarrow 5

Incorrect option

Posted by

prateek

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