Get Answers to all your Questions

header-bg qa

 Let a, b, c and d be non-zero numbers. If the point of intersection of the lines 4ax+2ay+c=0   and 5bx+2by+d=0 lies in the fourth quadrant and is equidistant from the two axes then :

  • Option 1)

    3bc-2ad=0

  • Option 2)

    3bc+2ab=0

  • Option 3)

    2bc-3ad=0

  • Option 4)

    2bc+3ad=0

 

Answers (2)

As learnt in

Condition of concurrency -

Solve the equations of two lines to get a point and satisfy it in the third equation of line.

-

 

 4ax+2ay+c=0 and 5bx+2by+d=0

Let the point of intersection be (K, -K)

From both equations, we get 

2aK+c = 0;3bK+d=0

                                       

=> K\:=\:\frac{-c}{2a}\:=\:\frac{-d}{3b}\\\\=> 3bc-2ad\:=0


Option 1)

3bc-2ad=0

This option is correct.

Option 2)

3bc+2ab=0

This option is incorrect.

Option 3)

2bc-3ad=0

This option is incorrect.

Option 4)

2bc+3ad=0

This option is incorrect.

Posted by

Vakul

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE