Let a, b, c and d be non-zero numbers. If the point of intersection of the lines 4ax+2ay+c=0   and 5bx+2by+d=0 lies in the fourth quadrant and is equidistant from the two axes then : Option 1) Option 2) Option 3) Option 4)

As learnt in

Condition of concurrency -

Solve the equations of two lines to get a point and satisfy it in the third equation of line.

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4ax+2ay+c=0 and 5bx+2by+d=0

Let the point of intersection be (K, -K)

From both equations, we get

2aK+c = 0;3bK+d=0

$=> K\:=\:\frac{-c}{2a}\:=\:\frac{-d}{3b}\\\\=> 3bc-2ad\:=0$

Option 1)

This option is correct.

Option 2)

This option is incorrect.

Option 3)

This option is incorrect.

Option 4)

This option is incorrect.

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