6.02 \times 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is:

  • Option 1)

    0.1 M

  • Option 2)

    0.02 M

  • Option 3)

    0.01 M

  • Option 4)

    0.001 M

 

Answers (1)

As we learnt in

no. of moles = \frac{6.02 \times 10^{20}}{6.02 \times 10^{23}} mol = 10-3

 

Vol. = 100 ml

Molarity, M = \frac{10^{-3}}{10^{-1}} \ M = 10^{-2}M = 0.01 M 


Option 1)

0.1 M

This option is incorrect.

Option 2)

0.02 M

This option is incorrect.

Option 3)

0.01 M

This option is correct.

Option 4)

0.001 M

This option is incorrect.

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