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How many moles of magnesium phosphate, Mg_{3}(PO_{4})_{2} will contain 0.25 mole of oxygen atoms?

Option 1)

0.02

 Option 2)

3.125 × 10-2
Option 3)

1.25 × 10-2

 Option 4)

2.5 × 10-2

Answers (2)

best_answer

As we learnt in

Number of Moles -

No of moles = given mass of substance/ molar mass of substance

-

 

 8 moles of oxygen atom present in one mole Mg3(PO4)2

So the 0.25 mole oxygen atom present in \frac{0.25\times 1}{8}=3.125\times10^{2}\ moles

Answer. Option (2)


Option 1)

0.02

This is an incorrect option.

Option 2)

3.125 × 10-2

This is the correct option.

Option 3)

1.25 × 10-2

This is an incorrect option.

Option 4)

2.5 × 10-2

This is an incorrect option.

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Aadil

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