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  • Tell me? The correct order of increasing basicity of the given conjugate bases (R = CH3) is

The correct order of increasing basicity of the given conjugate bases (R = CH3) is

  • Option 1)

    RCOO^{-}< HC\equiv C^{-}< NH_{2}^{-}< R^{-}

  • Option 2)

    RCOO^{-}< HC\equiv C^{-}<R^{-}< NH_{2}^{-}

  • Option 3)

    R^{-}< HC\equiv C^{-}<RCOO^{-}< NH_{2}^{-}

  • Option 4)

    RCOO^{-}< NH_{2}^{-}< HC\equiv C^{-}<R^{-}

 

Answers (1)

best_answer

As we have learned

Conjugate acid base pair -

If bronsted acid is a strong acid then its conjugate base is a weak base and vice versa.

- wherein

HCl+H_{2}O\rightleftharpoons H_{3}O^{+}+Cl^{-}

Cl- is conjugate base of  HCl  &  H3O+  is conjugate acid of  H2O.

 

 Stronger acids has weaker conjugate base aciding order : 

RCOOH > HC \equiv CH>NH_3>RH

So basicity order : RCOO^- < HC \equiv C^- < NH_2^- < R^-

 

 

 

 

 


Option 1)

RCOO^{-}< HC\equiv C^{-}< NH_{2}^{-}< R^{-}

Option 2)

RCOO^{-}< HC\equiv C^{-}<R^{-}< NH_{2}^{-}

Option 3)

R^{-}< HC\equiv C^{-}<RCOO^{-}< NH_{2}^{-}

Option 4)

RCOO^{-}< NH_{2}^{-}< HC\equiv C^{-}<R^{-}

Posted by

SudhirSol

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