The current  I   drawn from the 5  volt source will be :

  • Option 1)

    0.17 A

  • Option 2)

    0.33 A

  • Option 3)

    0.5 A

  • Option 4)

    0.67 A

 

Answers (2)
V Vakul

As we learnt in

Wheat stone Bridge -

It is an arrangement of four resistances which can be used to measure one of them in terms of rest

- wherein

 

The equivalent circuit is a balanced Wheatstone's bridge. Hence no current flows through arm BD 

AB and BC are in series

\therefore R_{ABC}= 5+10=15\Omega

AD \; and \; AC \: are \; in \; series

\therefore R_{ADC}= 10+20=30\Omega

ABC \; and\; ADC \; are\; in\; paralle

\therefore R_{eq}= \frac{\left ( R_{ABC} \right )\left ( R_{ADC} \right )}{\left (R_{ABC}+R_{ADC} \right )}

or\: \: \: \: R_{eq}=\frac{15\times 30}{15+30}= \frac{15\times 30}{45}= 10\Omega

\therefore Current\; \; I= \frac{E}{R_{eq}}= \frac{5}{10}= 0.5A

 

 


Option 1)

0.17 A

This option is incorrect.

Option 2)

0.33 A

This option is incorrect.

Option 3)

0.5 A

This option is correct.

Option 4)

0.67 A

This option is incorrect.

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