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The minimum velocity (in ms-1) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is

  • Option 1)

    60

  • Option 2)

    30

  • Option 3)

    15

  • Option 4)

    25

 

Answers (1)

As we learnt in

Skidding of Vehicle on a Level Road -

Frictional force \geq Req. centripetal Force

\mu mg \geq \frac{mv^{2}}{r}

V_{safe}\leq \sqrt{\mu rg}

V_{safe}=Safe vector move

r = radius of curve

\mu= coefficient of friction

- wherein

V_{safe} is the maximum velocity by which vehicle can turn on a circular path of radius r. 

 

 

 

 

For no skidding along curved track,

\nu = \sqrt{0.6\times 150\times 10}=30\ ms^{-1}

Correct option is 2.


Option 1)

60

This is an incorrect option.

Option 2)

30

This is the correct option.

Option 3)

15

This is an incorrect option.

Option 4)

25

This is an incorrect option.

Posted by

Vakul

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