The velocity-time graphs of a car and a scooter are shown in the figure. (i) The difference between the distance travelled by the car and the scooter in 15 s and (ii) the time at which the car will catch up with the scooter are, respectively.
112.5 m and 22.5 s
337.5 m and 25 s
112.5 m and 15 s
225.5 m and 10 s
As we learned
Position time graph for uniform motion -
when object moving along straight line covers equal distances in equal intervals of time, it is said to be in uniform motion along a straight line.
- wherein
Figure shows position time graph for uniform motion.
distance traveled by scooter = 30*15 = 450m
distance traveled by Car =
difference between distance traveled by scooter and car after 15 sec = 112.5m
total at car catch up with scooter then 30t = 337.5+45(t-15)
or 30t = 337.5+45t-675
or 15t = 337.5
t = 22.5sec
Option 1)
112.5 m and 22.5 s
Option 2)
337.5 m and 25 s
Option 3)
112.5 m and 15 s
Option 4)
225.5 m and 10 s
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