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Term "active mass" shows the concentration of reactants and products in:

Option: 1

mol\, dm^{-3} for a dilute solution


Option: 2

mol\,cm^{-3} for a dilute solution


Option: 3

mol\,cm^{-3}  for a concentrated solution.


Option: 4

mol\, dm^{-3}  for a concentrated solution.


Answers (1)

best_answer

Term "active mass" shows the concentration of reactants and products in mol\, dm^{-3}

because of concentration = \frac{n}{v}   =  \frac{mol}{ litre}

and 1 litre = 1dm^{3}.

Therefore, the option number (1) is correct.

Posted by

Riya

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