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The above p-v diagram represents the thermodynamic cycle of an engine,operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is : 

Option: 1

4p_{0}v_{0}


Option: 2

p_{0}v_{0}


Option: 3

\left ( \frac{13}{2} \right )p_{0}v_{0}\; \;


Option: 4

\left ( \frac{11}{2} \right )p_{0}v_{0}\; \;


Answers (1)

best_answer

Heat is extracted from the source would be in paths DA and AB.

\\\text { Thus heat supplied }=n C_v\left(2 T_o-T_o\right)+n C_p\left(4 T_o-T_o\right)\\\\=\frac{n 3 R T_o}{2}+\frac{n 5 R\left(2 T_o\right)}{2} \\\\=\frac{13 n R T_o}{2}=\frac{13}{2} P_o V_o

Formula:

Volume is constant and when pressure is constant.

= \frac{Cv}{R} (P_{2}V_{2} -P_{1}V_{1})+\frac{Cp}{R} (P_{3}V_{3} -P_{2}V_{2})

Posted by

Shailly goel

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