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  • The active mass of 64 g of HI in a 2 L flask would be:Option: 1 2Option: 2 1

The active mass of 64 g of HI in a 2 L flask would be:

Option: 1

2


Option: 2

1


Option: 3

0.25


Option: 4

5


Answers (1)

best_answer

We know the formula-

\text { Active mass }=\frac{\textup{Given Mass}}{\mathrm{Molecular \ mass\times Volume}}


\textup{Active mass of }\mathrm{HI}=\frac{64}{128 \times 2}=0.25
Therefore, option(3) is correct

Posted by

Rishi

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