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The \mathrm{H} amount of thermal energy is developed by a resistor in 10 \mathrm{~s} when a current of 4 \mathrm{~A} is passed through it. If the current is increased to 16 \mathrm{~A}, the thermal energy developed by the resistor in 10 \mathrm{~s} will be :

Option: 1

\frac{\mathrm{H}}{4}


Option: 2

16 \mathrm{H}


Option: 3

4 \mathrm{H}


Option: 4

\mathrm{H}


Answers (1)

best_answer

\mathrm{H}=\mathrm{I}^{2} \mathrm{Rt}

\frac{\mathrm{H}_{1}}{\mathrm{H}_{2}}=\left(\frac{\mathrm{I}_{1}}{\mathrm{I}_{2}}\right)^{2}=\left(\frac{4}{16}\right)^{2}

\mathrm{H}_{2}=16 \mathrm{H}_{1}

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Sayak

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