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The amplitude of \mathrm{ 15 \sin (1000 \pi t)} is modulated by \mathrm{10 \sin (4 \pi t)} signal. The amplitude modulated signal contains frequency (ies) of
\mathrm{A. 500 \mathrm{~Hz}}
\mathrm{B. 2 \mathrm{~Hz}}
\mathrm{C. 250 \mathrm{~Hz}}
\mathrm{D. 498 \mathrm{~Hz}}
\mathrm{E. 502 \mathrm{~Hz}}
Choose the correct answer from the options given below:

 

Option: 1

A Only


Option: 2

B Only


Option: 3

A and B Only


Option: 4

A, D and E Only


Answers (1)

best_answer

\mathrm{\begin{aligned} & f_c=\frac{1000 \pi}{2 \pi}=500 \mathrm{~Hz} \\ & f_m=\frac{4 \pi}{2 \pi}=2 \mathrm{~Hz} \end{aligned} }
Upper side Band, \mathrm{ USB =\mathrm{f}_{\mathrm{c}}+\mathrm{f}_{\mathrm{m}} }
                          \mathrm{ U S B=502 \mathrm{HZ} }

Lower side Band,\mathrm{LS B=f_c-f_m }
                         \mathrm{ L S B=498 \mathrm{~Hz} }
 

Posted by

sudhir.kumar

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