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  • The amplitude of upper and lower side bands of A.M. wave where a carrier signal with frequency , peak voltage

The amplitude of upper and lower side bands of A.M. wave where a carrier signal with frequency 11.21 \mathrm{MHz}, peak voltage 15 \mathrm{~V} is amplitude modulated by a 7.7 \mathrm{kHz} sine wave of 5 \mathrm{~V} amplitude are \frac{\mathrm{a}}{10} \mathrm{~V}$ and $\frac{\mathrm{b}}{10} \mathrm{~V} respectively. Then the value of \frac{a}{b} is______
 

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\begin{gathered} f_{c}=11.21 \times 10^{6} \mathrm{~Hz} \\ A_{c}=15 \\ f_{m}=7.7 \times 10^{3} \mathrm{~Hz} \\ A_{m}=5 \mathrm{~V} \end{gathered}

\begin{aligned} \frac{a}{10}=\frac{b}{10} &=\frac{\mu A_{c}}{2} \\ \frac{a}{b} &=1 \end{aligned}

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