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The angular momentum for the electron in Bohr's orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, them the change in angular momentum will be

Option: 1

\frac{L}{2}


Option: 2

zero


Option: 3

L


Option: 4

2L


Answers (1)

best_answer

Angular momentum = \frac{\mathrm{nh}}{2 \pi}
\begin{aligned} & \mathrm{n}=1, \mathrm{~L}_1=\frac{\mathrm{h}}{2 \pi}=\mathrm{L} \\ & \mathrm{n}=2, \mathrm{~L}_2=\frac{2 \mathrm{~h}}{2 \pi}=2 \mathrm{~L} \\ & \Delta \mathrm{L}=2 \mathrm{~L}-\mathrm{L}=\mathrm{L} \end{aligned}

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SANGALDEEP SINGH

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