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The area bounded by y=x^{2},y=[x+1],x\leq 1 and the y-axis is (correctly upto two decimal point and don't round off)

Option: 1

0.33


Option: 2

0.66


Option: 3

1


Option: 4

2.33


Answers (1)

best_answer

 

Area between two curves -

If we have two functions intersection each other.First find the point of intersection.  Then integrate to find area

\int_{o}^{a}\left [ f\left ( x \right )-9\left ( x \right ) \right ]dx

- wherein

 

  

y=x^{2}\:\:\text{and}\:\:y= [ x ]+1

A=\int_{0}^{1}(1-x^{2})dx=\frac{2}{3}

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Anam Khan

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