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The atomic weight of \mathrm{Al} is 27. When current of 6 Faraday is passed through a solution of \mathrm{\mathrm{Al}^{3+}}  ion, the weight of \mathrm{\mathrm{Al}} deposited is

Option: 1

27 g


Option: 2

54 g


Option: 3

31 g


Option: 4

60 g


Answers (1)

best_answer

Eq of Al deposited = 6

wt of AI
\mathrm{Al} =6 \times \frac{27}{3} \\
\mathrm{=54 \mathrm{~g} }.
 

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Gunjita

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