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The Boolean expression $(p \wedge q) \Rightarrow((r \wedge q) \wedge p)$ is equivalent to :
Option: 1 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \wedge \mathrm{q})$
Option: 2 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \wedge \mathrm{q})$
Option: 3 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \wedge \mathrm{q})$
Option: 4 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \wedge \mathrm{q})$
Option: 5 $(q \wedge r) \Rightarrow(p \wedge q)$
Option: 6 $(q \wedge r) \Rightarrow(p \wedge q)$
Option: 7 $(q \wedge r) \Rightarrow(p \wedge q)$
Option: 8 $(q \wedge r) \Rightarrow(p \wedge q)$
Option: 9 $(\mathrm{p} \wedge \mathrm{r}) \Rightarrow(\mathrm{p} \wedge \mathrm{q})$
Option: 10 $(\mathrm{p} \wedge \mathrm{r}) \Rightarrow(\mathrm{p} \wedge \mathrm{q})$
Option: 11 $(\mathrm{p} \wedge \mathrm{r}) \Rightarrow(\mathrm{p} \wedge \mathrm{q})$
Option: 12 $(\mathrm{p} \wedge \mathrm{r}) \Rightarrow(\mathrm{p} \wedge \mathrm{q})$
Option: 13 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \vee \mathrm{q})$
Option: 14 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \vee \mathrm{q})$
Option: 15 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \vee \mathrm{q})$
Option: 16 $(\mathrm{p} \wedge \mathrm{q}) \Rightarrow(\mathrm{r} \vee \mathrm{q})$

Answers (1)

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Truth Table

$p$	$q$	$r$	$p\wedge q$	$(r\wedge q)\wedge p$	$(p\wedge q)\Rightarrow ((r\wedge q)\wedge p)$	$r\wedge q$	$( p\wedge q )\Rightarrow(r\wedge q)$
$T$	$T$	$T$	$T$	$T$	$T$	$T$	$T$
$T$	$T$	$F$	$T$	$F$	$F$	$F$	$F$
$T$	$F$	$F$	$F$	$F$	$T$	$F$	$T$
$T$	$F$	$F$	$F$	$F$	$T$	$F$	$T$
$F$	$T$	$T$	$F$	$F$	$T$	$T$	$T$
$F$	$T$	$F$	$F$	$F$	$T$	$F$	$T$
$F$	$F$	$T$	$F$	$F$	$T$	$F$	$T$
$F$	$F$	$F$	$F$	$F$	$T$	$F$	$T$

Posted by

Kuldeep Maurya

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