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The $\mathrm{I}-\mathrm{V}$ characteristics of a p-n junction diode in forward bias is shown in the figure. The ratio of dynamic resistance, corresponding to forward bias voltage of $2 \mathrm{~V}$ and $4 \mathrm{~V}$ respectively, is :

Option: 1
$1:2$

Option: 2
$5:1$

Option: 3
$1:40$

Option: 4
$20:1$

Answers (1)

best_answer

Dynamic resistance at $\mathrm{V= 2V}$
$\mathrm{R_{1}= \frac{\Delta V}{\Delta I}= \frac{2. 1-2}{10-5}}$
$\mathrm{R_{1}= 2\times 10^{-2}}$

Dynamic resistance at $\mathrm{V= 4V}$
$\mathrm{R_{2}= \frac{\Delta V}{\Delta I}= \frac{4. 2-4}{250-200}}$
$\mathrm{R_{2}= 0.4\times 10^{-2}}$

$\mathrm{\frac{R_{1}}{R_{2}}=5}$

The correct option is (2)

Posted by

SANGALDEEP SINGH

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