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  • The charged plates of a parallel plate capacitor is connected to a resistor. If key k is closed, the initial current i through the circuit is equal to i. Then the time constant of the circuit is eq

The charged plates of a parallel plate capacitor is connected to a resistor. If key k is closed, the initial current i through the circuit is equal to i. Then the time constant of the circuit is equal to

Option: 1

i/A


Option: 2

q/i
 


Option: 3

ia


Option: 4

none of these


Answers (1)

best_answer

\text { The initial voltage across the capacitor }=\frac{q}{C} \text { since } V_i+V_R=0 \text { according to kirchoff's law, }

\frac{q}{C}+i R=0

\Rightarrow \quad \mathrm{i}=\frac{\mathrm{q} / \mathrm{C}}{\mathrm{R}} \text { numerically }=\frac{\mathrm{q}}{\mathrm{RC}} \quad \Rightarrow \quad \mathrm{T}=\frac{\mathrm{q}}{\mathrm{i}} \text { where } T=R C=\text { time constant of } R-C \text { circuit. }

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