Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The Coefficient of  x^9 in  \left(x-{ }^{21} C_0\right)\left(x-{ }^{21} C_1\right)\left(x-{ }^{21} C_2\right) \ldots \ldots . .\left(x-{ }^{21} C_{10}\right) is

 

Option: 1

2^{40}-\frac{1}{2}{ }^{42} C_{20}


Option: 2

2^{39}-\frac{1}{2}{ }^{42} C_{21}


Option: 3

2^{40}-{ }^{42} C_{20}


Option: 4

2^{39}-\frac{1}{4}{ }^{42} C_{21}


Answers (1)

best_answer

Coefficient  x^{10}  = sum of products of { }^{20} C_0,{ }^{20} C_1 \ldots \ldots \ldots \ldots . .{ }^{20} C_{10}.  Taking ' 2 ' at a time.

On solving we will get option D

Posted by

jitender.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 1 exam in the last week of January; registration details
anam-khan

Over 656 UPSC, JEE, NEET, other coaching aspirants refunded more than Rs 1 crore: Govt
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET, UGC NET dates soon; websites to check

Latest Question