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The collector supply voltage is 6 \mathrm{~V} and the voltage drop across a resistor of \mathrm{600 \Omega} in the collector circuit is \mathrm{0.6 \mathrm{~V}}, in a transistor connector in common emitter mode. If the current gain is 20 , the base current is

Option: 1

0.25 \mathrm{~mA}


Option: 2

0.05 \mathrm{~mA}


Option: 3

0.12 \mathrm{~mA}


Option: 4

0.02 \mathrm{~mA}


Answers (1)

best_answer

The collector current is given by
\mathrm{\begin{aligned} & I_C=\frac{V_C}{R_C}=\frac{0.6 \mathrm{~V}}{600 \Omega}=1 \times 10^{-3} \mathrm{~A}=1 \mathrm{~mA} \\ & \beta=\frac{I_C}{I_B} \Rightarrow I_B=\frac{I_C}{\beta}=\frac{1 \mathrm{~mA}}{20}=0.05 \mathrm{~mA} \end{aligned} }

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chirag

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