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  • The correct order of energy of absorption for the following metal complexes is  <img alt="\mathrm{\mathrm{A}:\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}, \mathrm{B}:\left[\mathrm{

The correct order of energy of absorption for the following metal complexes is 

\mathrm{\mathrm{A}:\left[\mathrm{Ni}(\mathrm{en})_{3}\right]^{2+}, \mathrm{B}:\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}, \mathrm{C}:\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}}

Option: 1

\mathrm{C}<\mathrm{B}<\mathrm{A}


Option: 2

\mathrm{B}<\mathrm{C}<\mathrm{A}


Option: 3

\mathrm{C}<\mathrm{A}<\mathrm{B}


Option: 4

\mathrm{A}<\mathrm{C}<\mathrm{B}


Answers (1)

best_answer

Stronger the ligands the splitting will be large. If splitting is large the energy of absorption will high.

Increasing field strength : \mathrm{H}_2 \mathrm{O}<\mathrm{NH}_3<\mathrm{en}

So, energy of absorption : \mathrm{C<B<A}

Hence, the correct answer is Option (1).

Posted by

Ritika Harsh

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