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The correct order of following 3 \mathrm{d} metal oxides, according to their oxidation numbers is : \mathrm{(a) CrO _{3}\ \ (b) Fe _{2} O _{3}\ \ (c) MnO _{2}\ \ (d) V _{2} O _{5}\ \ (e) Cu _{2} O}
Option: 1 (\mathrm{d})>(\mathrm{a})>(\mathrm{b})>(\mathrm{c})>(\mathrm{e})
Option: 2 (a) >(\mathrm{c})>(\mathrm{d})>(\mathrm{b})>(\mathrm{e})
Option: 3 (a) >(\mathrm{d})>(\mathrm{c})>(\mathrm{b})>(\mathrm{e})
Option: 4 (\mathrm{c})>(\mathrm{a})>(\mathrm{d})>(\mathrm{e})>(\mathrm{b})

Answers (1)

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The oxidation state of the metal ions are

(a) \mathrm{CrO}_{3}:+6
(b) \mathrm{Fe}_{2} \mathrm{O}_{3}:+3
(c) \mathrm{MnO}_{2}:+4
(d) \mathrm{V}_{2} \mathrm{O}_{5}:+5
(e) \mathrm{Cu}_{2} \mathrm{O}:+1
Thus, the correct order of oxidation states of the central atom in the given compounds is

(a) >(\mathrm{d})>(\mathrm{c})>(\mathrm{b})>(\mathrm{e})

Hence,the correct answer is option (3)

Posted by

sudhir.kumar

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