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The correct order of melting points of hydrides of group 16 elements is :

Option: 1

\mathrm{H}_{2} \mathrm{~S}<\mathrm{H}_{2} \mathrm{Se}<\mathrm{H}_{2} \mathrm{Te}<\mathrm{H}_{2} \mathrm{O}


Option: 2

\mathrm{H}_{2} \mathrm{O}<\mathrm{H}_{2} \mathrm{~S}<\mathrm{H}_{2} \mathrm{Se}<\mathrm{H}_{2} \mathrm{Te}


Option: 3

\mathrm{H}_{2} \mathrm{~S}<\mathrm{H}_{2} \mathrm{Te}<\mathrm{H}_{2} \mathrm{Se}<\mathrm{H}_{2} \mathrm{O}


Option: 4

\mathrm{H}_{2} \mathrm{Se}<\mathrm{H}_{2} \mathrm{~S}<\mathrm{H}_{2} \mathrm{Te}<\mathrm{H}_{2} \mathrm{O}


Answers (1)

best_answer

Melting point of hydrides of group 16  elements 

H bonding and molar mass predominantly decides the melting poin of Hydrides in Group 16 elements.

In \mathrm{H_{2}O} , due to excessive Hydrogen bonding , its melting point is larger than that of the other Group 16 hydrides.

\mathrm{\therefore }  Order of melting point is 

\mathrm{H_{2}S< H_{2}Se< H_{2}Te< H_{2}O}

Option (1) is correct

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Rishi

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