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The correct order of nucleophilicity is

Option: 1

\mathrm{F}^{-}>\mathrm{OH}^{-}


Option: 2


Option: 3


Option: 4

\mathrm{NH}_{2}^{-}>\mathrm{NH}_{3}


Answers (1)

best_answer

While comparing nucleophiles of same period, the nucleophilic strength follows basic strength.

Thus, \mathrm{OH}^{-}>\mathrm{F}^{-}

Next, neutral species are poorer nucleophiles than their anionic form

\begin{aligned} \therefore \quad \mathrm{OH}^{-} &>\mathrm{H}_{2} \mathrm{O} \\ \end{aligned}

        \begin{aligned} \mathrm{RO}^{-} &>\mathrm{ROH} \end{aligned}

        \begin{aligned} \mathrm{NH}_{2}^{-}>\mathrm{NH}_{3} \\ \end{aligned}

Hence, Option (4) is correct.

Posted by

Pankaj Sanodiya

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