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  • The correct order of reduction potentials of the following pairs is  A. <img alt="\mathrm{Cl}_{2} | \mathrm{Cl}^{-}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmath

The correct order of reduction potentials of the following pairs is 

A. \mathrm{Cl}_{2} | \mathrm{Cl}^{-}

B. \mathrm{I}_{2} |\mathrm{I}^{-}

C. \mathrm{Ag}^{+} | \mathrm{Ag}

D. \mathrm{Na}^{+} | \mathrm{Na}

E. \mathrm{Li}^{+} | \mathrm{Li}

Option: 1

A>C>B>D>E


Option: 2

A>B>C>D>E


Option: 3

A>C>B>E>D


Option: 4

A>B>C>E>D


Answers (1)

best_answer

Fact based on the reduction potential values.

The correct order will be

\mathrm{Cl}_{2} | \mathrm{Cl}^{\ominus}>\mathrm{Ag}^{+}|\mathrm{Ag}>\mathrm{I}_{2}|\mathrm{I}^{\ominus}>\mathrm{Na}^{\oplus } |\mathrm{Na}>\mathrm{Li}^{\oplus} | \mathrm{Li}

Thus, the given electrode couple can be arranged in order of their reduction potential values as

 \mathrm{A>C>B>D>E}

Hence, the correct answer is option(1)

Posted by

Anam Khan

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