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The current flowig through an ac circuit is given by  \mathrm{I=5\sin \left ( 120\pi t \right )A}.

How long will the current take to reach the peak value starting from zero?

Option: 1

\mathrm{\frac{1}{60}s}


Option: 2

\mathrm{60s}


Option: 3

\mathrm{\frac{1}{120}s}


Option: 4

\mathrm{\frac{1}{240}s}


Answers (1)

best_answer

\mathrm{I=5 \sin (120 \pi t)} \\

\mathrm{t=0, I=0 }\\

\mathrm{5=5 \sin (120 \pi t)} \\

\mathrm{\sin (120 \pi t)=1} \\

\mathrm{120 \pi t=\frac{\pi}{2}} \\

\mathrm{t=\frac{1}{240} \text { second }}

Hence the correct answer is option 4.

Posted by

SANGALDEEP SINGH

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