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The current I1 (in A) flowing through $1\Omega$ resistor in the following circuit is:-
Option: 1 0.25
Option: 2 0.40
Option: 3 0.2
Option: 4 0.5

Answers (1)

best_answer

Ohms Law -

Ohm’s law

In a conductor, if all external physical conditions like temperature and pressure are kept constant the Current flowing through a conductor is directly proportional to the Potential difference across two ends.

$V\propto I$

$V=IR$

$R-$ Electric Resistance

The graph between V and I

The slope gives the resistance

The graph between V and I at different temperatures

Here T1>T2. The resistance of a conductor increases with increase in temperature

-

$R_{AB}=\frac{1}{2}+2=\frac{5}{2}$

$R_{CD}=2$

$R_{eq}=\frac{2.5*2}{2.5+2}=\frac{10}{9}$

$I=\frac{V}{R_{eq}}=\frac{10}{9}$

As

$\Delta V_{AB}= \Delta V_{CD}\\ \Rightarrow 2.5*I_2 =2*I_3...(1)$

and $I_2+I_3=I=\frac{10}{9 }...(2)$

From equation (1) and (2)

$I_3=\frac{50}{81} , I_2=\frac{40}{81} ,$

and $I_1= \frac{I_2}{2}=\frac{20}{81} = 0.2469$

$I_1= 0.25$ ( when considered up to two decimal point)

Or,

$I_1= 0.2$ (when considered up to one decimal point)

Answer given by the NTA is $I_1= 0.2$ But most appropriate answer is $I_1= 0.25$

Posted by

Ritika Jonwal

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