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The current required to be passed through a solenoid of 15 cm length and 60 turns in order to demagnetize a bar magnet of magnetic intensity 2.4 \times 10^7 \mathrm{Am}^{-1}is ________A.

Option: 1

6


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{H}=2.4 \times 10^3 \mathrm{~A} / \mathrm{m} \\ & \mathrm{H}=\mathrm{nI}=\frac{\mathrm{N}}{\ell} \mathrm{I} \\ & \mathrm{I}=\frac{\mathrm{H} \ell}{\mathrm{N}}=\frac{2.4 \times 10^3 \times 15 \times 10^{-2}}{60} \\ & \mathrm{I}=6 \mathrm{~A} \end{aligned}

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himanshu.meshram

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