The de Brogile wavelength of an electron in the 4th Bohr orbit is:
We have:
n =
n = 4
Therefore, Option(3) is correct
VITEEE 2025 Exam April 26: Shift 1 to begin at 9:30 am; hall ticket, marking scheme
VITEEE 2025 April 23 LIVE: BTech day 4 shift 2 ends; question paper analysis, marks vs ranks
VITEEE 2025 slot booking starts tomorrow on viteee.vit.ac.in
Create Your Account
To keep connected with us please login with your personal information by phone
Dont't have an account? Register Now