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  • The de Broglie wavelength of an electron having kinetic energy E is . If the kinetic energy of electron bec

The de Broglie wavelength of an electron having kinetic energy E is \lambda. If the kinetic energy of electron becomes  \frac{E}{4} , then its de-Broglie wavelength will be :

Option: 1

\frac{\lambda }{\sqrt2}


Option: 2

2{\lambda }


Option: 3

\frac{\lambda}{2}


Option: 4

\sqrt2{\lambda}


Answers (1)

best_answer

\begin{aligned} & \lambda=\frac{\mathrm{h}}{\mathrm{p}}=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}} \\ & \frac{\lambda_1}{\lambda_2}=\sqrt{\frac{\mathrm{E}_2}{\mathrm{E}_1}}=\sqrt{\frac{1}{4}}=\frac{1}{2} \\ & \lambda_2=2 \lambda \end{aligned}

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