The density of 3M solution of sodium chloride is 1.252 g mL-1. The molality of the solution will be :
(molar mass , NaCl = 58.5 g mol)
2.60 m
2.18 m
2.79 m
3.00 m
We know that molar mass of NaCl = 58.5g
Thus, number of moles of NaCl = given weight / molecular weight
Thus, mass of NaCl in 1L solution = 175.5g
Now, we have density = mass/ volume
Thus, mass of 1 litre of solution = 1000 x 1.252
= 1252g
Therefore, mass of water = 1252 - 175.2
= 1074.5g
Therefore, molality of solution = 3/1.0745
= 2.79
Therefore, Option(3) is correct
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