The diagonals of a parallelogram PQRS are along the lines x + 3y = 4 and 6x − 2y = 7. Then PQRS must be a
Rectangle
Square
Cyclic quadrilateral
Rhombus
Product of slopes of the diagonals = −1
i.e. diagonals are mutually perpendicular.
Hence PQRS is a rhombus,
Which is given in (d)
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