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The diameter of a spherical bob is measured using a vernier callipers. 9 divisions of the main scale, in the vernier callipers, are equal to 10 divisions of vernier scale. One main scale division is $1 \mathrm{~mm}.$ The main scale reading is $10 \mathrm{~mm}$ and $8^{\text {th }}$ division of vernier scale was found to coincide exactly with one of the main scale division. If the given vemier callipers has positive zero error of $0.04 \mathrm{~cm},$ then the radius of the bob is _________ $\times 10^{-2} \mathrm{~cm}$ .

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$9MSD=10VSD\\$

$1MSD=1mm\\$

$LC=1MSD-1VSD=0.1MSD\\$

$MSR=10mm\\$

$VCD\: or\: VSD=8\\$

$Zero \ \ error=+0.04cm\\$

$Reading(Diameter)=MSR+VSR+Zero \ \ correction\\$

$=10mm+LC\times VCD+\left ( -Zero\: error \right )\\$

$=10mm+\left ( 0.1 \right )\times8+\left ( -0.4mm \right )\\$

$Diameter=10.4mm$

$Radius=5.2mm=52\times10^{-2}cm$

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Ritika Jonwal

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