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The difference between threshold wavelengths for two metal surfaces A and B having work function \phi_{\mathrm{A}}=9 \mathrm{eV} and \phi_{\mathrm{B}}=4.5 \mathrm{eV} in nm is :

Option: 1

276


Option: 2

264


Option: 3

540

 


Option: 4

138


Answers (1)

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\begin{aligned} & \phi=\frac{\mathrm{hc}}{\lambda} \\ & \lambda_{\mathrm{A}}=\frac{1242}{9}=138 \mathrm{~nm} \\ & \lambda_{\mathrm{B}}=\frac{1242}{4.5}=276 \mathrm{~nm} \\ & \lambda_{\mathrm{B}}-\lambda_{\mathrm{A}}=276-138=138 \mathrm{~nm} \end{aligned}

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