Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The digits 1, 2, 3, 4, 5, 6, and 7 may be repeated to make how many numbers between 90 and 999?Option: 1 392<div cl

The digits 1, 2, 3, 4, 5, 6, and 7 may be repeated to make how many numbers between 90 and 999?

Option: 1

392


Option: 2

409


Option: 3

512

 


Option: 4

602


Answers (1)

best_answer

The given digits are 1, 2, 3, 4, 5, 6, and 7.

To find the numbers formed between 90 and 999.

Between 90 and 999, the numbers are 2-digit and 3-digit.

Each digit can be filled in 7 ways because repetition is allowed.

The number of the 2-digit numbers formed is given by,

7\times7=49
The number of the 3-digit numbers formed is given by,

7\times7\times=343

Thus, the total number of ways the numbers can be formed is,

49+343=392

Therefore, the number of ways is 392.

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exam 2025 Live: UGC NET admit card out for all exams; JEE Main session 1 hall ticket soon
anam-khan

SFI protests across Tamil Nadu universities against UGC draft regulations on faculty recruitment
anam-khan

How to get top rank in JEE Main 2025? Last 10-day study plan

Latest Question