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  • The disproportionation of in acidic medium resulted in the formation

The disproportionation of \mathrm{MnO}_{4}^{2-} in acidic medium resulted in the formation of two manganese compounds \mathrm{A}$ and $\mathrm{B}. If the oxidation state of \mathrm{Mn}$ in $\mathrm{B} is smaller than that of \mathrm{A}, then the spin-only magnetic moment \mathrm{(\mu)} value of B in BM is_________ . (Nearest integer)

Option: 1

4


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

                                    +7                 +4
\mathrm{\rightarrow MnO_{4}^{-2}\overset{H^{+}}{\longrightarrow}MnO_{4}^{-}+MnO_{2}}

- no.of unpaired electrons = 3 [3d3 configuration of Mn+4].

Hence, Magnetic moment \mathrm{\left ( \mu \right )= \sqrt{n\left ( n+2 \right )}\, B.M}
                                                   \mathrm{= \sqrt{3\left ( 2+3 \right )}= \sqrt{15}\, B.M}               
                                                                                 \mathrm{= 3.877\, B.M}

Nearest integer = 4 which is the answer.

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