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  • The distance between <img alt="\mathrm{Na}^{+}\text{and } \mathrm{Cl}^{-}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BNa%7D%5E%7B&plus;%7D%5Ctext%7Band%20%7D%20%5Cmathrm%7

The distance between \mathrm{Na}^{+}\text{and } \mathrm{Cl}^{-}ions in solid NaCl of density 43.1 g cm-3 is_________\times10^{-10}\text{m}.  (Nearest Integer)

\text { (Given : } \mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1} \text {) }

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} &\text { Density }=\frac{Z M_{0}}{N_{A} \; a^{3}}=43.1 \\ \\&\Rightarrow \quad \frac{4 \times 58.5}{6.02 \times 10^{23} \; a^{3}}=43.1 \end{aligned}

\begin{aligned} &\Rightarrow \quad a^{3}=9 \times 10^{-24} \\ &\Rightarrow \quad a=2.08 \times 10^{-8} \mathrm{~cm} \\ &\Rightarrow \quad a=2.08 \times 10^{-10} \mathrm{~m} \end{aligned}

Now in NaCl type of solid

\begin{aligned} & a=2\left(r_{+}+r_{-}\right) \\ \Rightarrow & r_{+}+r_{-}=\frac{a}{2}=1.04 \times 10^{-10} \mathrm{~m} \end{aligned}

Thus, the distance between \mathrm{Na^{+}\; and\; Cl^{-}} is 1.04\times10^{-10}\text{m}

Hence , the answer is 1

Posted by

Riya

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