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The distance of the point P(4,6,-2)  from the line passing through the point (-3,2,3) and parallel to a line with direction ratios 3,3,-1  is equal to : 

Option: 1

\sqrt{14}


Option: 2

3


Option: 3

\sqrt{6}


Option: 4

2 \sqrt{3}


Answers (1)

best_answer

equation of line


\overline{\mathrm{r}}=(-3,2,3)+\lambda(3,3,-1)
\overline{\mathrm{PM}} \cdot(3,3,-1)=0
(3 \lambda-7,3 \lambda-4,5-\lambda) \cdot(3,3,-1)=0
\Rightarrow 3(3 \lambda-7)+3(3 \lambda-4)-1(15-\lambda)=0
\Rightarrow 19 \lambda=38 \Rightarrow \lambda=2

\mathrm{M}=(3,8,1)
\mathrm{PM}=\sqrt{1+4+9}=\sqrt{14}
(-3+3 \lambda, 2+3 \lambda, 3-\lambda)

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chirag

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