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  • The electric current in a circular coil of 2 turns produces a magnetic induction at its centre. The coil is unwound and is

The electric current in a circular coil of 2 turns produces a magnetic induction \mathrm{B_{1}} at its centre. The coil is unwound and is rewound into a circular coil of 5 turns and the same current produces a magnetic induction \mathrm{B_{2}}  at its centre. The ratio of \mathrm{\frac{B_{2}}{B_{1}}} is

Option: 1

\frac{5}{2}


Option: 2

\frac{25}{4}


Option: 3

\frac{5}{4}


Option: 4

\frac{25}{2}


Answers (1)

best_answer

\mathrm{\l =n_1\left(2 \pi r_1\right)=n_2\left(2 \pi r_2\right)}

                          =\mathrm{Constant}

       
        \mathrm{\frac{n_1}{n_2}=\frac{r_2}{r_1}=\frac{2}{5}}
Magnetic field due to circular coil is

\mathrm{B =\frac{\mu_0 n_i}{2 r} }

\mathrm{\frac{B_1}{B_2} =\frac{n_1}{n_2} \times \frac{r_2}{r_1}=\frac{4}{25} }


\mathrm{\therefore \frac{B_2}{B_1} =\frac{25}{4}}

Hence (2) is correct option.



 

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Gaurav

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