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  • The electric field of a plane electromagneyic wave propagating along the x direction in vacuum is 

The electric field of a plane electromagneyic wave propagating along the x direction in vacuum is \vec{E}=E_{0}\; \hat{j}\cos (\omega t-kx) . The magnetic field \vec{B}, at the moment t=0 is :
Option: 1 \vec{B}=\frac{E_{0}}{\sqrt{\mu _{0}\epsilon _{0}}}\cos (kx)\hat{k}  
Option: 2 \vec{B}=E_{0}\sqrt{\mu _{0}\epsilon _{0}}\cos (kx)\hat{j}
Option: 3 \vec{B}=E_{0}\sqrt{\mu _{0}\epsilon _{0}}\cos (kx)\hat{k}
Option: 4 \vec{B}=\frac{E_{0}}{\sqrt{\mu _{0}\epsilon _{0}}}\cos (kx)\hat{j}

Answers (1)

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\begin{array}{l} E=E_{0} \cos (\omega t-k x) \hat{j} \\ E_0=B_0 C \\\\ B_0=\frac{E}{C}=\frac{E_{0}}{\frac{1}{\sqrt{\mu_{0} \in_{0}}}} \\ \\ B_0=E_{0} \sqrt{\mu_{0} \epsilon_{0}} \end{array}

\begin{array}{l} \mathrm{B}=\mathrm{E}_{0} \sqrt{\mu_{0} \epsilon_{0}} \cos (\omega \mathrm{t}-\mathrm{k} \mathrm{x}) \hat{\mathrm{k}} \\ \text { at } \mathrm{t}=0 \\ \overrightarrow{\mathrm{B}}=\mathrm{E}_{0} \sqrt{\mu_{0} \in_{0}} \cos (\mathrm{kx}) \hat{\mathrm{k}} \end{array}

 

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