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The e.m.f. of the cell in which the following reaction Z n_{(s)}+N i^{2+}(a=1.0) \Leftrightarrow Z n^{2+}(a=10)+N i_{(s)} occurs, is found to be 0.5105V at 298K. The standard e.m.fof the cell is

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\\ E_{\mathrm{cell}}=E_{\mathrm{cell}}^{\circ}-\frac{0.0592}{2} \log _{10}(\frac{[Zn^{2+}]}{[Ni^{2+}]}) \\\\ 0.5105=E_{\mathrm{cell}}^{\circ}-\frac{0.0592}{2} \log (\frac{10}{1}) \\\\ \text { or } E_{\text {coll }}^{\circ}=0.54 \mathrm{V}

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