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The energy levels of an hydrogen atom are shown below. The transition corresponding to emission of shortest
wavelength is

Option: 1

A


Option: 2

D


Option: 3

C


Option: 4

B


Answers (1)

best_answer

\begin{aligned} & E=\frac{h c}{\lambda} \\ & \Rightarrow \lambda=\frac{h c}{E} \end{aligned}
For \lambda_{\min }, \mathrm{E}must be maximum. And \mathrm{E} is maximum for \mathrm{D}.

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himanshu.meshram

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