Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The equation of the line bisecting perpendicularly the segment joining the points $(-4,6)$ and $(8,8)$ is
Option: 1
$6 x+y-19=0$

Option: 2
$y=7$

Option: 3
$6 x+2 y-19=0$

Option: 4
$x+2 y-7=0$

Answers (1)

best_answer

Equation of the line passing through $(-4,6)$ and $(8,8)$ is

$y-6=\frac{8-6}{8+4}(x+4) \Rightarrow y-6=\frac{2}{12}(x+4) \Rightarrow 6 y-x=40$ $........(i)$

Now equation of any line $\perp \text { to it is } 6 x+y+\lambda=0$ $........(ii)$

This line passes through the midpoint of $(-4,6)$ and $(8,8)$ i.e., $(2,7)$

$\therefore$ $\text { From (ii) } 12+7+\lambda=0 \Rightarrow \lambda=-19 \text {, }$ $\therefore \quad \text { Equation of line is }$

$6 x+y-19=0$

Posted by

chirag

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in

anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates

anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question