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  • The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point <img alt="\mathrm{(6,-3)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathr

The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point \mathrm{(6,-3)} is

Option: 1

\mathrm{y^2=12 x+6}


Option: 2

\mathrm{x^2=12 y}


Option: 3

\mathrm{x^2=-12 y}


Option: 4

\mathrm{y^2=-12 x+6}


Answers (1)

best_answer

Since the axis of parabola is y-axis with its vertex at origin.

\mathrm{\therefore}  Equation of parabola \mathrm{x^2=4 a y}. Since it passes through \mathrm{(6,-3) \, \, \, \, \, \, \, \, \, \, \, \, \, \quad ; \quad \therefore 36=-12 a \quad \Rightarrow a=-3}

\mathrm{\therefore} Equation of parabola is \mathrm{ x^2=-12 y}

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SANGALDEEP SINGH

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