Get Answers to all your Questions

header-bg qa

The free space inside a current carrying toroid is filled with a material of susceptibility 2\times 10^{-2}. The percentage
increase in the value of magnetic field inside the toroid will be

Option: 1

0.2%


Option: 2

1%


Option: 3

2%


Option: 4

0.1%


Answers (1)

best_answer

\begin{aligned} & \mathrm{X}=2 \times 10^{-2} \\ & \mu \mathrm{r}=1+\mathrm{x}=1+0.02=1.02 \end{aligned}
Bo \rightarrow magnetic field due to magnetic material

\mathrm{B}_{\mathrm{m}} \rightarrowmagnetic field due to magnetic material

\mathrm{B}_{\mathrm{m}}=\mu_{\mathrm{r}} \mathrm{B}_0
\Delta \mathrm{B}=\frac{\mathrm{B}_{\mathrm{m}}-\mathrm{B}_0}{\mathrm{~B}_0} \times 100=\frac{\mu_{\mathrm{r}} \mathrm{B}_0-\mathrm{B}_0}{\mathrm{~B}_0} \times 100
\Delta \mathrm{B} \%=\frac{(\mathrm{X}+1)-1}{1} \times 100=\mathrm{X} \times 100
\Delta \mathrm{B} \%=2 \times 10^{-2} \times 100=2 \%

Posted by

Rishabh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE