Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

The function  \mathrm{f(x)=1+|\sin x|}  is

Option: 1

continuous nowhere


Option: 2

discontinuous everywhere
 


Option: 3

differentiable nowhere


Option: 4

not differentiable at an infinite number of points


Answers (1)

best_answer

Since \mathrm{|\sin x|}  is every where continuous, therefore  \mathrm{f(x)=1+|\sin x|}  is everywhere continuous.
The function \mathrm{f(x)=1+|\sin x|}  is not differentiable at \mathrm{x=n \pi, n=0, \pm 1, \pm 2, \ldots}as shown below:

 

Posted by

Info Expert 30

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 1 exam in the last week of January; registration details
anam-khan

Over 656 UPSC, JEE, NEET, other coaching aspirants refunded more than Rs 1 crore: Govt
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET, UGC NET dates soon; websites to check

Latest Question